An atom of an element contains 29 electrons and 35 neutrons. Deduce (i) the number of protons and (ii) the electronic configuration of the element.

An atom of an element contains 29 electrons and 35 neutrons. Deduce (i

1.	An atom of an element contains 29 electrons and 35 neutrons. Deduce (i) the number of protons and (ii) the electronic configuration of the element.
Answer» Solution :For neutral atom, number of protons = number of electrons `=29` THUS, atomic number of the element `=29` Electronic configuration of element with `Z=29` will be : `1s^(2) 2s^(2) 2p^(6) 3s^(2) 3P^(6) 3d^(10) 4s^(1) or [Ar]^(18) 3d^(10) 4s^(1)`, i.e., `._(29)CU`. Mass number = No. of protons + No. of NEUTRONS `=29+35=64`