An atom of an element contains 35 electrons and 45 neutrons.Deduce(i)the number of protons(ii)the electronic configuration for the element(iii)All the four quantum numbers for the last electron

An atom of an element contains 35 electrons and 45 neutrons.Deduce(i)t

1.	An atom of an element contains 35 electrons and 45 neutrons.Deduce(i)the number of protons(ii)the electronic configuration for the element(iii)All the four quantum numbers for the last electron
Answer» Solution :An element X contains 35 ELECTRONS 45 electrons (i) The NUMBER of protons must be equal to the number of electrons.So the number of protons=35 (ii)Number of electrons =35 so the ELECTRONIC configuration is `1s^(2)2S^(2)2p^(6)3s^(2)3p^(6)4s^(2)3d^(10)4p^(2)` (iii) The last ELECTRON i.e `5^(h)` electron in 4p orbital has the following quantum numbers. n=4,l=1,m=+1,s=-1/2