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An automatic machine produces 20000 pins per day. On rare occasion it produces a perfect pin whose chance is 1/10000 . Assuming Poisson distribution, the mean and variance of the number of perfect pins are respectively(a) √2 ,√2(b) 2, 2(c) 2, 4(d) 4, 2 |
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Answer» Correct answer is: (b) 2, 2 For Poisson distribution Mean = variance = np = 20000 × \(\cfrac{1}{10000}\) = 2 |
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