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An automobile engine develops `100` kilo`-`watt, when rotating at a speed of `1800 rev//min`. Find the torque developed by it. |
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Answer» The power delivered by the torque `tau` exerted on rotating body is given by `P = tau omega` or `tau = (P)/(omega)` Here `P = 100 KW = 100, 000` Watt `omega = ((1800)/(60)) xx 2 pi` =`60 pi rad//sec`, `tau = (10^(5))/(60 xx 3.14) = 531 N-m`. |
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