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An automobile moving with a uniform velocity of 500 ms-1 is brought to rest in travelling a distance of 5m. What is the acceleration produced by the brakes? |
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Answer» Initial velocity of the car, u = 500 ms-1 Final velocity of the car v = 0 Let a be the acceleration of the car. Then using the relation. v2 = u2 + 2aS 02 = 5002 + 2a × 5 a = -5002/10 = – 25 × 103ms-2. |
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