An automobile negotiates a turn of radius 40√3 m on a road which is banked at the curve at angle 30∘ to the horizontal. If coefficient of friction between road surface and automobile is 1√3 then maximum speed at which the car can negotiate the turn without skidding will be (g=10 m/s2)

An automobile negotiates a turn of radius 40√3 m on a road which is

1.	An automobile negotiates a turn of radius 40√3 m on a road which is banked at the curve at angle 30∘ to the horizontal. If coefficient of friction between road surface and automobile is 1√3 then maximum speed at which the car can negotiate the turn without skidding will be (g=10 m/s2)
Answer» An automobile negotiates a turn of radius $\frac{40}{\sqrt{3}} m$ on a road which is banked at the curve at angle $30^{\circ}$ to the horizontal. If coefficient of friction between road surface and automobile is $\frac{1}{\sqrt{3}}$ then maximum speed at which the car can negotiate the turn without skidding will be $(g = 10 {m/s}^{2})$

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An automobile negotiates a turn of radius 40√3 m on a road which is banked at the curve at angle 30∘ to the horizontal. If coefficient of friction between road surface and automobile is 1√3 then maximum speed at which the car can negotiate the turn without skidding will be (g=10 m/s2)

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