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An effusion experiment requires `40 s` of a certain number of moles of a gas of unknown molar mass to pass through a small orifice into a vaccum. Under the same conditions, `16 s` was required for the same number of moles of `O_(2)` to effuse. What is the molar mass of the unknown gas?A. `5.1 g//mol`B. `12.8 g//mol`C. `80 g//mol`D. `200 g//mol` |
Answer» Correct Answer - D `(t_((gas)))/(t(O_(2)))=sqrt(M_((gas))/(M_((O_(2)))))` `implies(40)/(16)=sqrt(M_((gas))/(32))` `implies (5)/(2)=sqrt(M_((gas))/(32))implies (25)/(4) =(M_((gas)))/(32)` `implies M_(gas)= 200 g// mol` |
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