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An elecric current 0.25 ampere was passed through acidified water for two hours, the volume of `H_(2)` produced at N.T.P isA. 20.16 litresB. 0.2016litresC. 2.016litresD. 0.4032 litres. |
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Answer» Correct Answer - B `W=(E)/(96500)xxIxxt` `=(1)/(96500)xx0.25xx2xx60=0.01865g` `2gH_(2)` has volume =22.4 litre `0.01865g` of `H_(2)` has volume `=(22.4)/(2)xx0.01865=0.2016` litre. |
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