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An electric bulb is connected to a source of 200V and current through circuit is 0.5 ampere what will resistance and power of bulb |
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Answer» V=200 V I=0.5 A By ohm's law : V=IR R=V/I=200/0.5=400 ohms power=VI=200*0.5=100 Watts. PLEASE MARK AS BRAINLIEST.
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