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An electric bulb of resistance 200Ω draws a current of 1 Ampere. Calculate the power of the bulb the potential difference at its ends and the energy in kWh consumed burning it for 5h. |
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Answer» Power of the bulb, P = l2R = (1)2 x 200 ⇒ P = 200 W Energy consumed by bulb in 5h in burning = Power x Time = 200 x 5 = 1000 Wh = 1 kWh |
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