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InterviewSolution
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An electric bulb of volume `250`cc was sealed during manufacturing at a pressure of `10^(-3)mm` of mercury at `27^(@)C`. Compute the number of air molecules contained in the bulb. Avogadro constant `=6xx10^(23)mol^(-1),` density of mercury`=13600kgm^(-3)` and `g=10ms^(-2)`. |
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Answer» Correct Answer - A `pV = nRT` `:. n = (p V)/(RT) = ((rho g h)V)/(RT)` `= ((13.6 xx 10^3)(9.8)(10^-6)(250 xx 10^-6))/(8.31 xx 300)` `= 1.33 xx 10^-8` `:.` Number of molecules = `(n) N_A` `= (1.33 xx 10^-8)(6.02 xx 10^23)` `= 8 xx 10^15`. |
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