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An electric charge `+q` moves with velocity `vecv=3hati+4hatj+hatk`,in an electromagnetic field given by: `vecE=3hati+hatj+2hatk` and `vecB=hati+hatj+3hatk`.The `y`-component of the force experienced by `+q` is:A. `7 q`B. `5 q`C. `3 q`D. `2 q` |
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Answer» Correct Answer - 1 `vecF=q[vecE+vecvxxvecB]=F_(y)=7q hatj` |
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