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An electric current of 100 mA is passed through an electrolyte for 2 hours, 20 minutes and 20 seconds. Find the quantity of electricity passed. |
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Answer» Given : Electric current = I = 100 mA = 100 × 10-3A = 0.1 A Time = t = 2 hrs + 20 min + 20 s = 2 × 60 × 60 + 20 × 60 + 20 = 8420 s The quantity of electricity = Q = ? Q = I × t = 0.1 × 8420 = 842 C ∴ Quantity of electricity passed, Q = 842 C |
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