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An electric dipole consists of charges `+ 2e and -2e` separated by 0.78mm. It is an electric field of strength `3.4xx10^(6) N//C`. Calculate the magnitude of the torque on the dipole when the dipole moment is (a) parallel to (b) perpendicular to, and (c) antiparallel to the electric field. |
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Answer» Correct Answer - (a) Zero, (b) `8.5xx10^(-22) N m` (c ) Zero (a) `tau = pE sin theta = pE sin 0^(@) = 0` (b) `tau = pE sin theta` `= (2e) (0.78xx10^(-9)) 3.4xx10^(6) xx sin 90^(@)` `= 2xx1.6xx10^(-19) xx0.78xx3.4xx10^(-3)` `= 8.5xx10^(-22) Nm` |
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