1.

An electric dipole consists of two unlike charges of magnitude 2 × 10-6 C separated by 4 cm. The dipole is placed in an external field of 105 N/C. Find the work done by an external agent to turn the dipole through 180°.

Answer»

Data: q = 2 × 10-6

2l = 4cm = 4 × 10-2 m. 

E = 105 N/C, 

θ = 180° + θ0

Let us assume the dipole is initially aligned parallel to the field, i.e., θ0 = 0.

Then, θ = 180°. 

The work done by an external agent,

W = pE(1 – cos θ)

= q (2l) E(1 – cos 180°)

= (2 × 10-6 C)(4 × 10-2m)(105 N/C) [1 – (-1)]

= 16 × 10-3 J



Discussion

No Comment Found

Related InterviewSolutions