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An electric dipole consists of two unlike charges of magnitude 2 × 10-6 C separated by 4 cm. The dipole is placed in an external field of 105 N/C. Find the work done by an external agent to turn the dipole through 180°. |
Answer» Data: q = 2 × 10-6 , 2l = 4cm = 4 × 10-2 m. E = 105 N/C, θ = 180° + θ0 Let us assume the dipole is initially aligned parallel to the field, i.e., θ0 = 0. Then, θ = 180°. The work done by an external agent, W = pE(1 – cos θ) = q (2l) E(1 – cos 180°) = (2 × 10-6 C)(4 × 10-2m)(105 N/C) [1 – (-1)] = 16 × 10-3 J |
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