1.

An electric dipole has a fixed dipole moment vecp which makes angle 9 with respect to X-axis. When subjected to an electric field vecE_(1) = Ejhati ,it experience a torque vecT_(1) = tauveckWhen subjected to another electric field vecE_(2) = sqrt(3)E_(1)hatjit experiences a torque vecT_(2) - vecT_(1). The angle theta is:

Answer»

`60^(@)`
`90^(@)`
`30^(@)`
`45^(@)`

Solution :
`vectau_(1) = VECP xx vecE`
`=(p_(x)hati + p_(y)hatj) xx Ehati`
`=-p_(y)Ehatk`………..(1)
and `vectau_(2) =(p_(x)hati + p_(y)hatj) xx sqrt(3)Ehatj`
`=sqrt(3)p_(x)Ehatk`………(2)
but `vectau_(2) =-vectau_(1)`
But `vectau_(2) =-vectau_(1)`
`therefore sqrt(3)p_(x)Ehatk =-(-p_(y)Ehatk)`
`therefore sqrt(3)=tan THETA` (From figure)
`therefore theta = 60^(@)`


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