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InterviewSolution
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An electric dipole has opposite charges of magnitude 2 × 10-15 C separated by 0.2 mm. It is placed in a uniform electric field of 103 N/C. (i) Find the magnitude of the dipole moment. (ii) What is the torque on the dipole when the dipole moment is at 60° with respect to the field? |
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Answer» Data : q = 2 × 10-15 C, 2l = 0.2 mm = 2 × 10-4 m, E = 103 N/C, θ = 60° (i) The magnitude of the dipole moment is V = q (2l) = (2 × 10-15 C) (2 × 10-4 m) = 4 × 10-19 C∙m (ii) The torque on the dipole is τ = pE sin θ = (4 × 10-19 C∙m) (103 N/C) sin 60° = 4 × 10-16 × 0.866 = 3.46 × 10-16 N∙m |
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