An electric dipole is placed in a uniform electric field `vec(E )` of magnitude `40N//C`. Graph shows the magnitude of the square on the dipole versus the angle `theta` between the field `vec(E )` and the dipole moment `vec(p)`. The magnitude of dipole moment `vec(p)` is equal to: A. `2.5 xx 10^(-28)Cm`B. `2.0 xx 10^(-25) Cm`C. `1.25 xx 10^(-28) Cm`D. `5.0 xx 10^(-28) Cm`

An electric dipole is placed in a uniform electric field `vec(E )` of

1.	An electric dipole is placed in a uniform electric field `vec(E )` of magnitude `40N//C`. Graph shows the magnitude of the square on the dipole versus the angle `theta` between the field `vec(E )` and the dipole moment `vec(p)`. The magnitude of dipole moment `vec(p)` is equal to: A. `2.5 xx 10^(-28)Cm`B. `2.0 xx 10^(-25) Cm`C. `1.25 xx 10^(-28) Cm`D. `5.0 xx 10^(-28) Cm`
Answer» Correct Answer - C `overset(rarr)tau=overset(rarr)pxxoverset(rarr)E` `vectau=vecpxxvecE` `tau_("mas")=pE` or `50xx10^(-28)=p40` or `p=1.25xx10^(-28)C`

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