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An electric dipole of length 4 cm, when placed with its axis making an angle of 60° with a uniform electric field, experiences a torque of 4√3 Nm. Calculate the potential energy of the dipole, if it has charge ±8 nC |
Answer» Torque, t = pE sin q 4√3 = pE sin 60° 4√3 = pE x √3/2 ⇒ pE = 8 Now, potential energy, U = -pE cos θ = -8 cos 60° = -8 x 1/2 = -4 J |
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