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An electric dipole of length 4 cm, when placed with its axis making an angle of `60^(@)` with a uniform electric field, experiences a torque of `4 sqrt(3) N m`. Calculate the a. magnitude of the electric field, and b. potential energy of the dipole, if the dipole has charges of `+- 8 n C`. |
Answer» Correct Answer - `-4 J` Here, `2a = 4cm = 4xx10^(-2) m, theta = 60^(@)`. `tau = 4 sqrt(3) Nm, q = +- 8nC = 8xx10^(-9)C` Now, `p = q xx 2a = (8xx10^(-9)) xx (4xx10^(-2)) Cm` `tau = pE sin theta or E = tau//p sin theta` `PE = -pE cos theta = -p xx (tau)/(p sin theta) xx cos theta` `= -tau cot theta = -4 sqrt(3)" " 60^(@)` `= -4 sqrt(3) xx 1//sqrt(3) = -4 J` |
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