1.

An electric discharge is passed through a mixture containing 50cc of O_(2) and 50cc of H_(2). The volume of the gases formed at 110^(@)C will be

Answer»

50cc
75cc
25cc
100cc

Solution :`2H_(2)+O_(2)rarr2H_(2)O`
`(50)/(2)lt(50)/(1)`
`implies H_(2)` is the L.R
`2ml H_(2)RARR 2ml H_(2)O`
`50ml H_(2)rarr50mlH_(2)O`
VOLUME of `O_(2)` used = 25ml implies leftover 25ml
`THEREFORE` TOTAL volume of gases = `50+25=75ml`


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