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An electric discharge is passed through a mixture containing 50 c.c. of `O_(2)` and 50 c.c. of` H_(2)`. The volume of the gases formed (i) at room temperature and (ii) at `110^(@)`C will beA. (a)(i) 25 c.c. (ii) 50 c.c.B. (b)(i) 50 c.c. (ii) 75 c.c.C. (c )(i) 25 c.c. (ii) 75 c.c.D. (d)(i) 75 c.c. (ii) 75 c.c. |
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Answer» Correct Answer - C At room temperature `2H_(2(g))+O_(2(g))rarr 2H_(2)O_((l))` `" "t=0 " " 50 ml" " 50 "ml"" "` 0 `" "t=t" " 50-2x" " 50-x" " 2x` `" " =0" "25 gases (50)` liquid In this case `H_(2)` is limiting reagent `x=25 ml` At `110^(@)C 2H_(2(g))+O_(2(g))rarr 2H_(2)O_((g)) V_(gas)=75 ml` `t=t" 0" " 25ml " "50ml` |
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