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An electric field of strength `E = 1.0 kV//cm` produces plarization in water equivalent to the correct orientation of only one out of `N` . The electric moment of a water molecule equals `p = 0.62.10^(-29)` C.m. |
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Answer» The total polarization is `P = (e - 1) epsilon_(0) E`. This must equals `(n_(0) p)/(N)` where `n_(0)` is the concertaition of water molecules. Thus `N = (n_(0) P)/((e - 1) epsilon_(0) E) = 2.93xx10^(3)` on putting the values |
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