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An electric field `vecE=4xhati-(y^(2)+1)hatjN//C` passes through the box shown in figure. The flux of the electric field through surface ABCD and BCGF are marked as `phi_1)and phi_(11)` respecticvely. The differentce between `(phi_(1)-phi_(1))` is in `Nm^(2)`/C)

Answer» Correct Answer - -48


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