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An electric iron consumes 1 kW electric power when operated at 220V. What should be the current rating of the fuse? |
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Answer» Here, P = 1 kW = 1000 W V = 220 V ∴Current, I = \(\frac{P}{V}\) = \(\frac{1000}{220}\) = 4.5 A Hence, to tolerate a current of 4.5 A, minimum of 5 A current rating fuse should be used. |
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