InterviewSolution
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InterviewSolution
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An electron, an `alpha`-particle and a proton have the same kinetic energy. Which of these particles has the largest de-Broglie wavelength? |
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Answer» Kinetic energy `K=1/2 mv^2=1/2 (m^2v^2)/m=1/2 (p^2)/m` or `p=sqrt(2mK)` De-Broglie wavelength, ` lambda=h/p=h/(sqrt(2mK))` `:. lambda prop1/(sqrtm)` (where K is constant) It means smallest is the particle mass, largest is the de-Broglie wavelength associated with it. Since the mass of electron is least out of the given particles, hence d-Broglie wavelength is largest for electron and least for `alpha`-particle. |
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