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An electron and proton enter a uniform magnetic field perpendicularly. Both have same kinetic energy. Which of the following is true? |
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Answer» Trajectory of electron is less curved or `qvB=(mv^(2))/r :. r=(mv)/(QB)` Now kinetic ENERGY of the PARTICLE, `K=1/2 mv^(2)rArr mv=sqrt(2mK)` Therefore, Eq(i) becomes `r=(sqrt(2mK))/(qB)` or `r prop sqrt(m)` `:. (r_(e))/(e_(p))=sqrt((m_(e))/(m_(p)))` As `m_(e) lt m_(p)` so, `r_(e) lt r_(p)` Hence , trajectory of proton is less curved. |
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