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An electron experiences a force equal to its weight, when placed in an electric field. The intensity of the field will beA. `4.36xx10^(-11)N//C`B. `5.573xx10^(-11)N//C`C. `6.67xx10^(-11)N//C`D. `9.86xx10^(-11)N//C` |
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Answer» Correct Answer - B `F=mg=eE` `therefore" "E=(mg)/e=(9.1xx10^(-31)xx9.8)/(1.6xx10^(-19))` `=5.573xx10^(-11)N//C` |
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