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An electron in an atom revolves around the nucleus in an orbit of radius `0*53Å`. Calculate the equivalent magnetic moment, if the frequency of revolution of electron is `6*8xx10^9MHz`. |
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Answer» Correct Answer - `9*6xx10^(-24)Am^2` Here, `r=0*53Å=0*53xx10^(-10)m` `v=6*8xx10^9MHz=6*8xx10^(15)Hz`, `M=?` If e is charge on electron, then the equivalent current, `I=e/T=ev` `M=IA=ev(pir^2)` `=1*6xx10^(-19)xx6*8xx10^(15)xx3*14(0*53xx10^(-10))^2` `=9*6xx10^(-24)Am^2` |
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