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An electron in the hydrogen atom circles around the proton with a speed of `2.18xx10^(6)`m/s in an orbit of radius `0.53Å` . The equivalent current isA. `1.048xx10^(-2)A`B. `1.048xx10^(-3)A`C. `1.048xx10^(-4)A`D. `1.058xx10^(-4)A` |
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Answer» Correct Answer - B `I=q/t=e/t=(e v)/(2 pi r)` `= (1.6xx10^(-19)xx2.18xx10^(6))/(6.28xx0.53xx10^(-10))` `=1.048 xx 10^(-3)A` |
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