1.

An electron in the hydrogen atom circles around the proton with a speed of `2.18xx10^(6)`m/s in an orbit of radius `0.53Å` . The equivalent current isA. `1.048xx10^(-2)A`B. `1.048xx10^(-3)A`C. `1.048xx10^(-4)A`D. `1.058xx10^(-4)A`

Answer» Correct Answer - B
`I=q/t=e/t=(e v)/(2 pi r)`
`= (1.6xx10^(-19)xx2.18xx10^(6))/(6.28xx0.53xx10^(-10))`
`=1.048 xx 10^(-3)A`


Discussion

No Comment Found

Related InterviewSolutions