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An electron is accelerated by a potential difference of 12000 volts. It then enters a uniform magnetic field of `10^(-3)T` applied perpendicular to the path of electron. Find the radius of path. Given mass of electron `=9xx10^(-31)kg` and charge on electron `=1.6xx10^(-19)C`A. 36.7 mB. 36.7 cmC. 3.67 mD. 3.67 cm |
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Answer» Correct Answer - A Radius `r=sqrT(2mK)/(qB)=(1)/(B)sqrt(2mV)/(q)` `=1/10^(-3)(2xx9xx10^(-31)xx1200)/(1.6xx10^(-19))` =0.367 m =36.7 cm |
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