An electron is in a 4f orbital. What possible vales for the quantum, n

1.	An electron is in a 4f orbital. What possible vales for the quantum, n, l, m and s can it have?
Answer» Solution :Since the electron is in a 4F ORBITAL, the value of the principle quantum number, n = 4 For the f-orbital, the SECONDARY quantum number, l = 3 The values of the MAGNETIC quantum (m) are `-l " to " +l` including zero. Therefore, when l = 3, m has seven values, i.e., `-3, -2, -1, 0, +1, +2, and 3` For each value of m, the spin quantum number, s has two values, i.e., `s = +1//2 and s = -1//2`

Discussion