An electron is moving round the nucleus of a hydrogen atom in a circular orbit of radius `r`. The coulomb force `vec(F)` between the two is (where `k=(1)/(4piepsilon_(0)))`A. `k(e^(2))/(r^(3))r`B. `-k(e^(2))/(r^(3))r`C. `k(e^(2))/(r^(2))r`D. `-k(e^(2))/(r^(3))hatr`

An electron is moving round the nucleus of a hydrogen atom in a circul

1.	An electron is moving round the nucleus of a hydrogen atom in a circular orbit of radius `r`. The coulomb force `vec(F)` between the two is (where `k=(1)/(4piepsilon_(0)))`A. `k(e^(2))/(r^(3))r`B. `-k(e^(2))/(r^(3))r`C. `k(e^(2))/(r^(2))r`D. `-k(e^(2))/(r^(3))hatr`
Answer» Correct Answer - B

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An electron is moving round the nucleus of a hydrogen atom in a circular orbit of radius `r`. The coulomb force `vec(F)` between the two is (where `k=(1)/(4piepsilon_(0)))`A. `k(e^(2))/(r^(3))r`B. `-k(e^(2))/(r^(3))r`C. `k(e^(2))/(r^(2))r`D. `-k(e^(2))/(r^(3))hatr`

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