InterviewSolution
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InterviewSolution
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An electron is projected with velocity `v_(0)` in a unifrom electric field E perpendicular to the field Again it is projectced with velocity `v_(0)` perpendicular to a unifrom magnetic field `B//` if `r_(1)` is initial radius of curvature just after entering in the electric field and `r_(2)` is initial radius of curvature just after entering in magnetic field then the ratio `r_(1)//r_(2)` is equal to .A. `(Bv_(0)^(2))/(E)`B. `(B)/(E)`C. `(Ev_(0))/(B)`D. `(Bv_(0))/(B)` |
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Answer» Correct Answer - D `eE = (mV_(0)^(2))/(r_(1)) implies r_(1) = (mV_(0)^(2))/(eE) ` `eV_(0)B = (mV_(0)^(2))/(r_(2)) = (mV_(0))/(eB) implies (r_(1))/(r_(2)) =(V_(0)B)/(E)` . |
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