An electron moves under a potential difference of 300 V 1. The wave a

1.	An electron moves under a potential difference of 300 V 1. The wave associated with electron is called……….2. Derive an expression for its wave in terms of charge of particle.3. Calculate the wavelength of above electron.
Answer» 1. matter wave 2. λ = \(\frac{h}{p}=\frac{h}{\sqrt{2meV}}\) = \(\frac{h}{\sqrt{2mqV}}\) 3. λ = \(\sqrt{\frac{150}{V}}A^0=\sqrt{\frac{150}{300}}=0.707A^0\)

An electron moves under a potential difference of 300 V 1. The wave associated with electron is called……….2. Derive an expression for its wave in terms of charge of particle.3. Calculate the wavelength of above electron.

Answer»

1. matter wave

2. λ = \(\frac{h}{p}=\frac{h}{\sqrt{2meV}}\) = \(\frac{h}{\sqrt{2mqV}}\)

3. λ = \(\sqrt{\frac{150}{V}}A^0=\sqrt{\frac{150}{300}}=0.707A^0\)