An electron moving with velocity 2.2 xx 10^(6) m/s, revolving in circular orbit of radius 0.53 Å. Calculate its angular velocity.

An electron moving with velocity 2.2 xx 10^(6) m/s, revolving in circu

1.	An electron moving with velocity 2.2 xx 10^(6) m/s, revolving in circular orbit of radius 0.53 Å. Calculate its angular velocity.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`v= 2.2 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(6)` m/s <br/> `r= 0.53 A= 0.53 xx 10^(-10)`m <br/> Angular velocity `<a href="https://interviewquestions.tuteehub.com/tag/omega-585625" style="font-weight:bold;" target="_blank" title="Click to know more about OMEGA">OMEGA</a>= (v)/(r)= (2.2 xx 10^(6))/(0.53 xx 10^(-10))` <br/> `omega= 4.15 xx 10^(16) rad s^(-1)`</body></html>