An electron moving with velocity 2.2 xx 10^(6) m/s, revolving in circular orbit of radius 0.53 Å. Calculate its angular velocity.

An electron moving with velocity 2.2 xx 10^(6) m/s, revolving in circu

1.	An electron moving with velocity 2.2 xx 10^(6) m/s, revolving in circular orbit of radius 0.53 Å. Calculate its angular velocity.
Answer» SOLUTION :`v= 2.2 XX 10^(6)` m/s `r= 0.53 A= 0.53 xx 10^(-10)`m Angular velocity `OMEGA= (v)/(r)= (2.2 xx 10^(6))/(0.53 xx 10^(-10))` `omega= 4.15 xx 10^(16) rad s^(-1)`