1.

An electron of charge `e` moves in a circular orbit of radius `r` round a nucleus the magnetic field due to orbit motion off the electron at the site of the nucleus is `B`. The angular velocity `omega` of the electron isA. `omega=(mu_(0)eB)/(4pir)`B. `omega=(mu_(0)eB)/(pir)`C. `omega=(4pirB)/(mu_(0)e)`D. `omega=(2pirB)/(mu_(0)e)`

Answer» Correct Answer - 3


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