An electron of mass 9 xx 10^(-31) kg revolves around a nucleus in a circular orbit of radius 0.53 Å. What is the angular momentum of the electron? (Velocity of electron is, v=2.2 xx 10^(6) ms^(-1)).

An electron of mass 9 xx 10^(-31) kg revolves around a nucleus in a ci

1.	An electron of mass 9 xx 10^(-31) kg revolves around a nucleus in a circular orbit of radius 0.53 Å. What is the angular momentum of the electron? (Velocity of electron is, v=2.2 xx 10^(6) ms^(-1)).
Answer» Solution :Mass of the electron, `m=9xx10^(-31)kg` Radius of the electron, `R=0.53 Åxx10^(-10)m` VELOCITY of the electron, `v=2.2xx10^(6)ms^(-1)` ngular momentum of ELECTRONIS, `L= I omega` Electron is CONSIDERED as a point mass. Hence, its moment of inertia is, `I -mr^(2)` The relation, `omega=(v)/(r)` could be used. Angular momentum,`L=mr^(2)xx(v)/(r)=mvr` `=9.1xx10^(-31)xx2.2xx10^(6)xx0.53xx10^(-10)` `L=1.06xx10^(-34) kg m^(2)s^(-1)` `=9.1xx10^(31)xx2.2xx10^(6)xx0.53xx10^(-10)` `L=1.06xx10^(-34) kgm^(2)s^(-1)`