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An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. Its final velocity will be-(a) \(\sqrt{\frac{2eV}{m}}\)(b) \(\sqrt{\frac{eV}{m}}\)(c) \(\frac{ev}{m}\)(d) \(\frac{ev}{m}\) |
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Answer» (a) \(\sqrt{\frac{2eV}{m}}\) K.E. gained by an electron when accelerated through a potential difference V, \(\frac{1}{2}\)mv = eV or v =\(\sqrt{\frac{2eV}{m}}\) |
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