InterviewSolution
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InterviewSolution
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An electron of mass `m_(e )` initially at rest moves through a certain distance in a uniform electric field in time `t_(1)`. A proton of mass `m_(p)` also initially at rest takes time `t_(2)` to move through an equal distance in this uniform electric field.Neglecting the effect of gravity, the ratio of `t_(2)//t_(1)` is nearly equal toA. `m_(p)/m_(e)`B. `(m_(p)/m_(e))^(2)`C. `(m_(p)/m_(e))^(1//2)`D. `(m_(p)/m_(e))^(3//2)` |
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Answer» Correct Answer - C `S=1/2at^(2)=((eE)/m)t^(2)` Now, `t^(2)/m` = Constant for same distance Thus, `mpropt^(2)` `therefore" "m_(e)/m_(p)=t_(e)^(2)/t_(p)^(2)" "thereforet_(p)/t_(e)=sqrt(m_(p)/m_(e))` `i.e" "t_(2)/t_(1)=(m_(p)/m_(e))^(1//2)` |
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