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| 1. |
An electron of mass `m` when accelerated through a potential difference `V` has de - Broglie wavelength `lambda`. The de - Broglie wavelength associated with a proton of mass `M` accelerated through the same potential difference will beA. `lambda m/M`B. `lambda M/m`C. `lambdasqrt(m/M)`D. `lambdasqrt(M/m)` |
| Answer» Correct Answer - 3 | |