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An element `A` decays into element `C` by a two-step process : `A rarr B + ._2 He^4` `B rarr C + 2 e overline` Then.A. A and C are isotopesB. A and C are isobarsC. B and C are isotopesD. A and B are isobars |
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Answer» Correct Answer - a `._Z^A A to ._(Z-2)^(A-4)B + ._2^4He ` `._(Z-2)^(A-4)B to ._Z^(A-4)C + 2_(-1)^0 e` Hence, A and C are isotopes |
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