An element A in a compound AB has oxidationnumber -n. IT is oxidized by Cr_(2)O_(7)^(2-) in acid medium. In the experiment 1.68xx10^(-3) moles of K_(2)Cr_(2)O_(7) was usedfor 3.36xx10^(-3) moles of AB. The new oxidation number of A after oxidation is

An element A in a compound AB has oxidationnumber -n. IT is oxidized b

1.	An element A in a compound AB has oxidationnumber -n. IT is oxidized by Cr_(2)O_(7)^(2-) in acid medium. In the experiment 1.68xx10^(-3) moles of K_(2)Cr_(2)O_(7) was usedfor 3.36xx10^(-3) moles of AB. The new oxidation number of A after oxidation is
Answer» 3 3 - n n - 3 `+n` Solution :`n= (1.68xx10^(-3))/(6xx 3.2 xx10^(-3))` `A^(n-)OVERSET(+n)rarrA^(X)` `1/(x+n)` moles `A^(n-),` `overset(+12)(Cr_2)overset(2-)(O_7)overset((6))rarr2cv^(3+)` `-=1/6` moles `Cr_(2)O_(7)^(2-)=1.68 xx10^(-3)` `(x+n)Cr_(2)O_(7)^(2-)-=6A^(n-)` `1.6 8810^(-3)""?` `=(1.68 xx10^(-3)xx6)/(x+n)=3.26xx10^(-3)` x = 3 - n