An element (atomic mass=250 u) crystallizes in a simple cubic. If the density of the unit cell is 7.2 g cm^(-3),what is the radius of the element ?

An element (atomic mass=250 u) crystallizes in a simple cubic. If the

1.	An element (atomic mass=250 u) crystallizes in a simple cubic. If the density of the unit cell is 7.2 g cm^(-3),what is the radius of the element ?
Answer» `1.93times10^(-3)CM` `1.93times10^(-8) cm` `1.93times10^(-8)Å` `1.93times10^(-8)m` SOLUTION :`d=(ZtimesM)/(a^(3)timesN_(0))therefore7.2=(1times250)/(a^(3)times6.02times10^(23))` or`a^(3)=57.6times10^(-24)` or`a=3.86times10^(-8)` For simple cubic, `r=a//2=1.93times10^(-8)` cm