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An element crystallize in f.c. lattice with cell edge of 250 pm. Calculate the density if 300 g of this element contains2 xx 10^(24)atoms. |
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Answer» Density `(p)= (Z xx M)/(a^(3)xxN_(0))= (4xx90.3)/((250xx10^(-10))^(3) xx (6.02 xx 10^(23))) = 38.4 " g mol" ^(-3)` |
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