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An element crystallize in f.c. lattice with cell edge of 250 pm. Calculate the density if 300 g of this element contains ` 2 xx 10^(24) ` atoms. |
Answer» Correct Answer - ` a = 5.94 xx 10^(-8) cm , V = a^(3) = 2.096 xx 10^(-22) cm^(3) ` Molar mass of the emlment (M) = `( 300)/(2xx 10^(24)) xx 6.02xx 10^(23) = 90.3 " g mol"^(-1)` Density `(p)= (Z xx M)/(a^(3)xxN_(0))= (4xx90.3)/((250xx10^(-10))^(3) xx (6.02 xx 10^(23))) = 38.4 " g mol" ^(-3)` |
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