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An element crystallizes in a f.c.c. lattice with cell edge of 250 pm. Calculate the density if 300 g of this element contains 2 xx 10^24 atoms |
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Answer» Density`(RHO)=(ZxxM)/(a^3xxN_0)=(4xx90.3)/((250xx10^(-10))^3xx(6.02xx10^23))=38.4 g cm^(-3)` |
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