1.

An element crystallizes in a f.c.c. lattice with cell edge of 250 pm. Calculate the density if 300 g of this element contains 2 xx 10^24 atoms

Answer»


Solution :MOLAR mass of the element (M)=`300/(2xx10^24)xx6.02xx10^23=90.3 g mol^(-1)`
Density`(RHO)=(ZxxM)/(a^3xxN_0)=(4xx90.3)/((250xx10^(-10))^3xx(6.02xx10^23))=38.4 g cm^(-3)`


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