InterviewSolution
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InterviewSolution
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An element exists in bcc lattice with a cell edge of 288 pm. Calculate its molar density is `7.2g//cm^(3)` |
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Answer» (ii) BCC lattice. Hence `z=2` `a=288p m=288xx10^(-12)m` `d=7.2g//cm^(3)` `d=(ZxxM)/(a^(3)xxNa)impliesM=(d xx a^(3)xxNa)/(Z)` `M=(7.2xx(288xx10^(-10))xx6.022xx10^(23))/(2)` `M=3.6xx288xx288xx288xx10^(-7)xx6.022` `M=51.8g//mol` |
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