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An element having an atomic radius of 0.14 nm crystallises in a fcc unit cell. What is the length of side of the cell ?A. 0.56 nmB. 0.24 nmC. 0.96 nmD. 0.4 nm

Answer» Correct Answer - D
For fcc unit cell , `r=(sqrt2)/(4)a`
`rArr " " 0.14=(sqrt2)/(4)a`
`a=(4xx0.14)/(sqrt2)=0.396nm=0.4nm`


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