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An element occupies group no.13 and period number 2 is an representative element of that group reacts with carbondioxide and forms an oxide (A). (A) reacts with CuSO_(4) give blue beads (B). Identify the element compound (A) and (B). Write the reaction. |
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Answer» Solution :As per the position in the periodic table this element which occupies group number 13 and period number 2 is BORON and it reacts with `CO_(2)` to form boric oxide 1) `3CO_(2)+4Brarr2B_(2)O_(3)+3C` `therefore` the COMPOUND A is `B_(2)O_(3)` 2) `B_(2)O_(3)` reacts with `CuSO_(4)` to form `underset(("Red"))((CuBO_(2))_(2))` `CuSO_(4)+B_(2)O_(3)rarrCu(BO_(2))_(2)+SO_(3)` `therefore` the compound B is copper BEAD. `Cu(BO_(2))_(2)` |
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